Friday, November 15, 2019
Laplace transforms
Laplace transforms    Laplace Transforms ââ¬â Motivation  convenience   ââ¬â differential eqns become algebraic eqns.  ââ¬â easy to handle time delays  ââ¬â frequency response analysis to determine how the system responds to oscillating inputs   Block Diagram Algebra  ââ¬â doing math with pictures  ââ¬â arithmetic for manipulating dynamic components using boxes and arrows  Laplace Transform ââ¬â Review    Given a function f(t)  Notes   f(t)  defined for t from 0 to infinity  f(t)  suitably ââ¬Å"well-behavedâ⬠  ââ¬â piecewise continuous, integrable  Linearity of Laplace Transforms  the Laplace transform is a linear operation    we will use Laplace transforms to analyze linear dynamic systems  if our models arent linear, then we will linearize   Useful Laplace Transforms for Process Control  We need a small library of Laplace transforms for   ââ¬â differentiation  ââ¬â step input  ââ¬â pulse/impulse functions  ââ¬â exponentials  ââ¬â oscillating functions   because these are common functions that we will encounter in our equations   Lets think about a simple linear differential equation example:   with V and F as constants  Library of Useful Transforms  differentiation  ââ¬â initial conditions disappear if we use deviation variables that are zero at an in initial steady state  unit step function (Heaviside fn.)  Library of Transforms  exponential  ââ¬â exponentials appear in solutions of differential equations  à » a provides information about the speed of the response when the input changes. If a is a large negative number, the exponential decays to zero quickly   à » What happens if a is positive?  ââ¬â After we have done some algebra to find a solution to our ODEs in the Laplace domain, we must invert the Laplace transform if we want to get a solution in the time domain. We sometimes use partial fraction expansion to express the Laplace expressions in a form that can be easily inverted.   CSTR Example  Transform Model (in deviation variables) using our library of transforms, the Laplace transform of the model is: For a step change in feed concentration at time zero starting from steady state. Tank Example  Solution   Solve for CA(s)    If we like, we can rearrange to the form: This is the solution in the Laplace domain. To find the solution in the time domain, we must invert the Laplace transforms  CSTR Example Solution  inverse Laplace transform   ââ¬â Can be determined using a complex integral  easiest approach is ââ¬Å"table lookupâ⬠    Use Table 4-1, entry 5    Maple is good at inverting Laplace transforms too  The Impulse Function   limit of the pulse function (with unit area) as the width goes to zero and height becomes infinite transform  CSTR  Impulse Response physically  dump some pure A into reactor, all at once input function Transform     time response   Interpretation of Impulse Response dump a bag of reactant into the reactor in a very very short time   we see an instantaneous jump to a new concentration due to the impulse input   concentration then decays back to the original steady-state concentration   Time-Shifted Functions  Representation of Delays Laplace transform for function with time delay   Just pre-multiply by an exponential.   How could we prove this?   ââ¬â change of variables in integration in expression for Laplace Transform (see p. 103 of Marlin, p. 115 in first ed.)  Reactor Example with Time Delay  Suppose we add a long length of pipe to feed  ââ¬â assume plug flow  ââ¬â It will take a time period, q minutes, before the change in   concentration reaches the tank, and begins to influence cA   ââ¬â delay differential equation  à » difficult to solve directly in time domain  à » easy to solve with Laplace transforms   Tank Example with Time Delay ââ¬â Solutionresponse to step input in cA0 time response   Final Value Theorem An easy way to find out what happens to the output variable if we wait a long time. We dont have to invert the Laplace transform!   Why is it true?  ââ¬â Consider the Laplace transform of a time derivative now let s approach zero  provided dy/dt isnt infinite between t=0 and tà ®Ã ¥ (i.e y(t) is STABLE) This will be true if Y(s) is continuous for sà ³0  Using the Final Value Theorem  Step Response Reactor example  final value after a step input  What can we do with Laplace Transforms so far.  Take Laplace transforms of linear ODEs (in deviation variables).  Substitute Laplace transform expressions for different kinds of inputs we are interested in:  ââ¬â Steps, pulses, impulses (even with dead time)  Solve for the output variable in terms of s.    Invert the Laplace transform using Table 4.1 to get the solution in the time domain.      Find the final steady state value of the output variable, for a particular input change, even without inverting the Laplace transform.    Laplace transforms are mostly used by control engineers who want to determine and analyze transfer functions.    compact way of expressing process dynamics    relates input to output    p(s), q(s)  polynomials in s  ââ¬â q(s) will also contain exponentials if time delay is present  Once we know the transfer function of the process, we can use it to find out how the process responds to different types of input changes:    
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